2y^2-2.42=0

Solution for 2y^2-2.42=0 equation:

2y^2-2.42=0

a = 2; b = 0; c = -2.42;
Δ = b2-4ac
Δ = 02-4·2·(-2.42)
Δ = 19.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{19.36}}{2*2}=\frac{0-\sqrt{19.36}}{4}
=-\frac{\sqrt{}}{4}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{19.36}}{2*2}=\frac{0+\sqrt{19.36}}{4}
=\frac{\sqrt{}}{4}
$